Concrete Cutting Sawing Acushnet MA Mass Massachusetts
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The
reinforcement at the center of the height would be .0084 >< 9.4 = .079
square inch per inch of width. This could be obtained by using finch bars about
5 inches apart, or by using finch bars about 7 inches apart. The selection and
spacing of bars can thus be made for the entire height. While there is no
method of making a definite calculation for the steel required in a vertical
direction, it may be advisable to use inch bars spaced about 18 inches
apart. We shall assume that the concrete baseplate has a width of onehalf the
height of the concrete wall, or is 10 feet wide. If the inner face of the
faceplate is 2 feet 6 inches from the toe, the width of the concrete baseplate
sustaining the earth pressure is 7 feet 6 inches.
The actual pressure on the concrete
baseplate is that due to the total weight of the earth. The upward pull on the
concrete buttresses is less than this, and is measured by the moment of the
horizontal pressure tending to tip the concrete wall over. To resist this
overturning tendency, there must be a downward pressure on the plate whose moment
equals the moment of the couple tending to turn the concrete wall over. The
pressure on the concrete wall on a vertical strip one foot wide, as found
above, is 6,400 pounds, which has a leverarm, about the center of the base of
the faceplate, of 6 feet 8 inches. The vertical pressure to resist this will
be applied at the center of the 7foot 6inch base, or 4 feet 5 inches from the
center of the faceplate. This means an average pressure of 1,287 pounds per
square foot. Making a similar calculation for this concrete baseplate to that
previously made for the faceplate, we find that the thickness d = 19.1 inches.
This shows that our concrete baseplate should have a total thickness of about
22 inches. The amount of steel per inch of width of the concrete slab equals
.0084 X 19.1 = .160 square inch. This can be provided by iinch
bars spaced 4 inches apart, or by 1inch bars spaced 6 inches apart. This
reinforcement will be uniform across the total width of the base plate. The
total pressure on a vertical strip one foot wide is 6,400 pounds. For a panel
of 15 feet, this equals 96,000 pounds; and its moment about the base of the concrete
wall equals 96,000 x 80 inches = 7,680,000 inchpounds. If the tiebars in the concrete
buttresses are placed about 3 inches from the face of the concrete buttresses,
their distance from the center of the base of the faceconcrete wall will be
about 89 inches.
Therefore the tension in the bars in each buttress will equal
7,680,000 = 86,292 pounds. Since the earth pressures considered above are
actual pressures, we must here consider working stresses in the metal. Allowing
15,000 pounds' tension in the steel, it will require 5.75 square inches of
steel for the tiebar of each buttress. Six 1inch square bars will more than
furnish this area. Even these bars need not all be extended to the top of the
buttress, since the tension is gradually being transferred to the faceplate. The
width of the buttress is not very definitely fixed. It must have enough volume
to contain the bars properly, without crowding them. In this case, for the six
1inch bars, we shall make the width 12 inches. At the base of the concrete
buttresses, these bars should be bent around bars running through the concrete
baseplate, so that the lower part of the buttress will be very thoroughly
anchored into the concrete baseplate. It is also necessary to tie the buttress
to the faceplate. The amount of this tension is definitely calculated for each
foot of height, from the total pressure on the faceplate in each panel for
that particular foot of height. At a depth of 19.5 feet, we found a bursting
pressure of 624 pounds per square foot, or 9,360 pounds on the 15foot panel.
This would therefore be the required bond between the buttress and the
faceplate at a depth of 19.5 feet.
Are You in Acushnet
Massachusetts? Do You Need Concrete Cutting?
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Concrete Cutter
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